b^2=2b+80

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Solution for b^2=2b+80 equation:


Simplifying
b2 = 2b + 80

Reorder the terms:
b2 = 80 + 2b

Solving
b2 = 80 + 2b

Solving for variable 'b'.

Reorder the terms:
-80 + -2b + b2 = 80 + 2b + -80 + -2b

Reorder the terms:
-80 + -2b + b2 = 80 + -80 + 2b + -2b

Combine like terms: 80 + -80 = 0
-80 + -2b + b2 = 0 + 2b + -2b
-80 + -2b + b2 = 2b + -2b

Combine like terms: 2b + -2b = 0
-80 + -2b + b2 = 0

Factor a trinomial.
(-8 + -1b)(10 + -1b) = 0

Subproblem 1

Set the factor '(-8 + -1b)' equal to zero and attempt to solve: Simplifying -8 + -1b = 0 Solving -8 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -1b = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -1b = 0 + 8 -1b = 0 + 8 Combine like terms: 0 + 8 = 8 -1b = 8 Divide each side by '-1'. b = -8 Simplifying b = -8

Subproblem 2

Set the factor '(10 + -1b)' equal to zero and attempt to solve: Simplifying 10 + -1b = 0 Solving 10 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1b = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1b = 0 + -10 -1b = 0 + -10 Combine like terms: 0 + -10 = -10 -1b = -10 Divide each side by '-1'. b = 10 Simplifying b = 10

Solution

b = {-8, 10}

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